Answer:
2.459 seconds or approximately 2.46 s
Step-by-step explanation:
We know, Time period = 2*π*√(l/g), where:
- l = effective length of pendulum
- g = acceleration due to gravity at that place
We are given the value of 'l' or effective length as 1.5 m
Let us assume the value of g as 9.8 m/s²
Putting the values,
- T = 2*(22/7)*√((1.5)/(9.8))
- T = 44/7*0.391
- T = 2.459 or approximately, 2.46 seconds
Hence to complete 1 oscillation, time required= 2.46 s approx.