Question

a ball hits a wall horizontally at 6m/s. it rebounds horizontally at 4.4m/s. the ball is in contact with the wall for 0.04s. what is the acceleration of the ball?

Answer 1

40 m/s²

Step-by-step explanation:

Given,

Initial velocity of the ball = 6 m/s

Since the ball rebounds(comes back after hitting the wall) so its final velocity stands at 4.4 m/s, as given.

Final velocity of ball = 4.4 m/s

Time = 0.04 s, i.e. the time interval during which the ball hitted the wall and then rebounded against it.

To find,

Acceleration.

We know, acceleration = Change in velocity upon time, mathematically:

• Acceleration = (v-u)/t where v = final velocity, u = initial velocity and t = time interval.

Putting the values,

• Acceleration = (6-4.4)/0.04

Simplifying,

• 1.6/0.04 = a
• 16*10/4 = a
• 40 m/s² = a

Hence,the ball has an acceleration of 40 m/s² .