Answer:
Explanation:
Steve's net displacement for the entire trip can be calculated by finding the difference between his final position and his initial position. In this case, Steve drove from his house to the store, which was 3.54 km away, and then walked back home. Since he returned to his starting point, his net displacement for the entire trip is 0 km.
To find the distance Steve traveled during the trip, we can add up the distances he traveled during each leg of the trip. Steve drove to the store, which was 3.54 km away, and then walked back home. So the total distance traveled by Steve during the trip is 3.54 km + 3.54 km = 7.08 km.
To calculate Steve's average velocity for the whole trip, we need to divide his total displacement by the total time taken. As mentioned earlier, Steve's net displacement for the entire trip is 0 km. The total time taken for the trip is 9 minutes (driving to the store) + 37 minutes (walking back home) = 46 minutes. Therefore, Steve's average velocity for the whole trip is 0 km/46 min = 0 km/min.
Finally, to find Steve's average speed for the whole trip, we divide the total distance traveled by the total time taken. As calculated earlier, the total distance traveled is 7.08 km and the total time taken is 46 minutes. Steve's average speed for the whole trip is 7.08 km/46 min = 0.154 km/min (rounded to three decimal places).
In summary:
a. Steve's net displacement for the entire trip is 0 km.
b. Steve traveled a total distance of 7.08 km during the trip.
c. Steve's average velocity for the whole trip is 0 km/min.
d. Steve's average speed for the whole trip is approximately 0.154 km/min.