Question

Using the table of electronegativities provided arrange the following bonds in order of increasing ionic character. (Place the least polar bond at the top of the list.) C-H F-Cl N-O Pd-H

Answer 1

To arrange the bonds in order of increasing ionic character, which correlates with the electronegativity difference, the general order is C-H (least polar), Pd-H, N-O, and F-Cl (most polar). This assumes no specific values provided.

Step-by-step explanation:

The student's question is about arranging chemical bonds in order of increasing ionic character. The ionic character of a bond is related to the electronegativity difference between the two atoms involved in the bond. Generally, a greater difference indicates a more polar (and thus more ionic) bond. To rank the bonds from least to most polar, we consider the atoms' electronegativities using the given table or periodic trends.

For the given bonds C-H, F-Cl, N-O, and Pd-H, we expect the following general trends based on electronegativity:

1. C-H (carbon and hydrogen have a small electronegativity difference)
2. Pd-H (palladium and hydrogen also have a relatively small difference, but the exact value would depend on specific data from the electronegativity table provided)
3. N-O (nitrogen and oxygen have a moderate electronegativity difference)
4. F-Cl (fluorine and chlorine have the greatest electronegativity difference of the pairs listed)

So, the order from least polar to most polar (and therefore increasing ionic character) would be:

1. C-H
2. Pd-H
3. N-O
4. F-Cl

If detailed electronegativity values are provided, these could be used to refine the order between C-H and Pd-H.