134k views
5 votes
When polynomial P is divided by
x^2-x-6, the remainder is 4x-7, what is P(2) and P(3)?

User Juggeli
by
7.6k points

1 Answer

2 votes
If polynomial P is divided by x - 2, and the remainder is 4x - 7, then you can use the Remainder Theorem to find P(2) and P(3).

The Remainder Theorem states that when you divide a polynomial P(x) by (x - a), the remainder is P(a). In this case, a = 2.

So, to find P(2), substitute x = 2 into the remainder, which is 4x - 7:
P(2) = 4(2) - 7
P(2) = 8 - 7
P(2) = 1

To find P(3), you can do the same:
P(3) = 4(3) - 7
P(3) = 12 - 7
P(3) = 5

So, P(2) = 1 and P(3) = 5.
User HOY
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories