To determine the magnitude and orientation of the airplane's position vector at t = 55.0 s, we can subtract the initial position vector from the final position vector.
P55 - PO = (6.92*10^3î + 8.15*10^3j) - 8.15*10^3j
Simplifying this expression, we get:
P55 = (6.92*10^3î)
The magnitude of the airplane's position vector at t = 55.0 s is 6.92*10^3 meters, and its orientation is along the x-axis.