Answer:
**No, 219 mL is not right.**
To calculate the volume of stock solution needed, we can use the following equation:
Volume of stock solution = (Molarity of desired solution * Volume of desired solution) / Molarity of stock solution
Where:
* Molarity of desired solution = 2.55 mol/L
* Volume of desired solution = 1.50 L
* Molarity of stock solution = (36.0% HCl by mass * 1000 g/L) / (36.5 g/mol HCl) = 986.3 mol/L
Plugging these values into the equation, we get:
```
Volume of stock solution = (2.55 mol/L * 1.50 L) / 986.3 mol/L = 4.576 mL
```
Therefore, the volume of stock solution needed is **4.576 mL**.
**Answer: False**