161k views
2 votes
Is 219mL right?

An aqueous stock solution is 36.0% HCl by mass and its density is 1.18 g/mL. What volume of this solution is required to make 1.50 L of 2.55 mol/L HCl(aq)?

1 Answer

2 votes

Answer:

**No, 219 mL is not right.**

To calculate the volume of stock solution needed, we can use the following equation:

Volume of stock solution = (Molarity of desired solution * Volume of desired solution) / Molarity of stock solution

Where:

* Molarity of desired solution = 2.55 mol/L

* Volume of desired solution = 1.50 L

* Molarity of stock solution = (36.0% HCl by mass * 1000 g/L) / (36.5 g/mol HCl) = 986.3 mol/L

Plugging these values into the equation, we get:

```

Volume of stock solution = (2.55 mol/L * 1.50 L) / 986.3 mol/L = 4.576 mL

```

Therefore, the volume of stock solution needed is **4.576 mL**.

**Answer: False**

User Chen Houwu
by
7.5k points

No related questions found