149k views
1 vote
If the graphs of the lines 2x -5y=7 and 10x+by=7

are perpendicular, what is the value of b?

User Andreis
by
7.8k points

1 Answer

4 votes

Answer: b = 4

Explanation:

If the slope of a line is m, the slope of the perpendicular line would be the negative reciprocal i.e. -1/m

So let's find the slope of 2x-5y = 7.

2x - 5y = 7 (subtract 5y on both sides)

2x = 7 + 5y (subtract 7 on both sides)

2x - 7 = 5y (divide by 5 on both sides)

2/5 x - 7/5 = y OR y = 2/5x - 7/5

Therefore, the slope of 2x-5y = 7 is 2/5.

The perpendicular line will therefore have a slope of -5/2

Once we rearrange the second line 10x + by = 7

We end up with:

by = 7 - 10x

y = 7/b - 10/bx

So we set:

-10/b = -5/2

10 = 5b/2

20 = 5b

20/5 = b --> b=4

User Nick Van Brunt
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories