Question

A racing car moving at 53.8 m/s engages a parachute and braking system. It comes to rest 5.60 s later. Determine the displacement of the racing car during this deceleration period.

Answer 1

Final V squared = initial V squared + (2 acceleration * displacement)

Rearrange the formula:

Displacement = (Final V Squared - initial V squared)/ 2(acceleration).

We know vf = 0 m/s, vi = 53.8 m/s, and
a is the acceleration which we can find using the equation of motion

a =Δv/Δt

Δv is the change in velocity, which is −53.8 m/s (negative because it's deceleration), and Δt is the change in time, which is 5.60 seconds.

So, a = -53.8/5.60

Now, plug these values into the displacement formula:

S = ((0m/s)^2 - (53.8m/s)^2) / 2 * (-53.8m/s / 5.60s)

S = 150.91m