Answer: Y = -2x + 11
Explanation:
To find an equation of a line parallel to the line passing through the point (4,3) with the equation y = -2x - 1, we need to use the fact that parallel lines have the same slope.
The given line has a slope of -2. So, the parallel line we are looking for will also have a slope of -2.
To find the equation of the parallel line, we can use the point-slope form of a linear equation, which is:
y - y1 = m(x - x1)
where m is the slope of the line and (x1, y1) is a point on the line.
Using the point (4,3) and the slope -2, we have:
y - 3 = -2(x - 4)
Now, we can simplify and rearrange the equation to get it in the standard form (y = mx + b), where m is the slope and b is the y-intercept:
y - 3 = -2x + 8
y = -2x + 8 + 3
y = -2x + 11
Therefore, the equation of the line parallel to y = -2x - 1 and passing through the point (4,3) is y = -2x + 11