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Write an equation of the line parallel to the line passing through the point y=-2x-1(4,3)

User CmdLP
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Answer: Y = -2x + 11

Explanation:

To find an equation of a line parallel to the line passing through the point (4,3) with the equation y = -2x - 1, we need to use the fact that parallel lines have the same slope.

The given line has a slope of -2. So, the parallel line we are looking for will also have a slope of -2.

To find the equation of the parallel line, we can use the point-slope form of a linear equation, which is:

y - y1 = m(x - x1)

where m is the slope of the line and (x1, y1) is a point on the line.

Using the point (4,3) and the slope -2, we have:

y - 3 = -2(x - 4)

Now, we can simplify and rearrange the equation to get it in the standard form (y = mx + b), where m is the slope and b is the y-intercept:

y - 3 = -2x + 8

y = -2x + 8 + 3

y = -2x + 11

Therefore, the equation of the line parallel to y = -2x - 1 and passing through the point (4,3) is y = -2x + 11

User AriX
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