Question

at when adults with smartphones are randomly selected, 48% use them in meetings or classes. If 13 adult smartphone users are randomly selected, find the hat fewer than 3 of them use their smartphones in meetings or classesAssume that when adults with smartphones are randomly selected, 48% use them in meetings or classes. If 13 adult smartphone users are randomly selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.

Answer 1

This is a binomial probability problem. We can use the formula for binomial probability, which is:

P(X=k) = C(n, k) * (p^k) * ((1-p)^{n-k})

where:

- P(X=k) is the probability of k successes in n trials,

- C(n, k) is the number of combinations of n items taken k at a time,

- p is the probability of success on a single trial.

Given that the probability of an adult using their smartphone in meetings or classes is 48% or 0.48, and we are selecting 13 adults, we want to find the probability that fewer than 3 of them use their smartphones in meetings or classes. This means we want to find P(X=0) + P(X=1) + P(X=2).

Explanation: