Question

A balloon is filled with 9.55 moles of helium gas with a volume of 3.03 L. If the

temperature of the helium is 303 K, what is the pressure of the gas in the balloon?

Answer 1

The pressure is 7,939.87 kPA

Step-by-step explanation:

The Ideal Gas Law is PV=nRT

In this equation,

n = 9.55 moles,

T = 303 K,

V = 3.03 L,

and R is our ideal gas constant,

R = 8.314 J/mol^-1.

So, plugging in these numbers

(P)(3.03)=(9.55)(8.314)(303),

P=7,939.87 kPa.