Question

Keisha is catering a luncheon. she has $30 to spend on a mixture of cheddar cheese and swiss cheese. how many pounds of cheese can keisha get if she only buys cheddar cheese? only swiss cheese? a mixture of both cheeses? what linear equation in standard form can she use to model the situation?

if she only buys cheddar, and she spends all $30, she can buy ___ pounds.

Answer 1

how many pounds of cheese can keisha get if she only buys cheddar cheese?

Cheddar is $3/lb. She has $30.

So $30/$3 = 10 lbs of cheddar

only swiss cheese?

Swiss is $5/lb. She has $30.

So $30/$5 = 6 lbs of swiss

what linear equation in standard form can she use to model the situation?

The standard form for linear equations in two variables is Ax+By=C.
Let X = lbs of cheddar

Let y = lbs of swiss cheese

C = the total money she has, which is $30

A = cost per lb of cheddar, which is $3

B = cost per lb of swiss which is $5

Ax + By = C

3x + 5y = $30

a mixture of both cheeses?

You could use a lot of different combinations here.

So she can buy any combination of cheeses on that line - - - for example, if she buys 1 lb of cheddar (which costs $3), she would have 30-3 = $27 left for swiss. She can buy 27/5 = 5.4 lbs of swiss. So if she buys 1 lb of cheddar, she can buy 5.4 lbs of swiss.