Question

Find the equation of the line that passes through the given point and has the given slope.

(−5, 14), m = −2
Part 1 of 4
The point-slope formula is
y − y1 = m(x − x1).
Substitute the coordinates of the point (−5, 14) in the point-slope formula.
y − 14 = m(x −




)

y − 14 = m

x +

Answer 1

## Part 1 of 4

The point-slope formula is

```

y - y1 = m(x - x1)

```

where m is the slope of the line and (x1, y1) is a point on the line.

Substitute the coordinates of the point (-5, 14) and the slope -2 into the point-slope formula:

```

y - 14 = -2(x - (-5))

```

```

y - 14 = -2(x + 5)

```

Now, we can simplify the equation by distributing the -2 on the right-hand side:

```

y - 14 = -2x - 10

```

Finally, we can add 14 to both sides to isolate y:

```

y = -2x - 10 + 14

```

```

y = -2x + 4

```

Therefore, the equation of the line is **y = -2x + 4**.

Explanation:

I got lost on the United Kingdom server, btw I'm from Indonesia

Answer 2

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Answer: y = -2x + 4

Explanation:

We're asked to find the equation of the line that passes through (-5,-14) and has a slope of -2.

I am going to start by using the point-slope formula:

⇒
`\boldsymbol{y-y_1=m(x-x_1)}`

Substitute the values:

⇒
`\boldsymbol{y-14=-2(x-(-5)}`

⇒
`\boldsymbol{y-14=-2(x+5)}`

Next, distribute -2:

⇒
`\boldsymbol{y-14=-2x-10}`

Add 14 to both sides:

⇒
`\boldsymbol{y=-2x-10+14}`

⇒
`\boldsymbol{y=-2x+4}`

Therefore, our equation is y = -2x + 4.

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