Final answer:
The total number of possible configurations for 6 female and 5 male soccer players selected from 8 females and 7 males is calculated by finding the combinations for each and multiplying them together, giving us 588 as the answer.
Step-by-step explanation:
The question at hand is a combinatorics problem, involving the selection of soccer players from a group for a particular formation in a match. To determine the number of possible configurations for the team, we will calculate the combinations of choosing 6 females out of 8 and 5 males out of 7, and then multiply these two numbers since the choices are independent of each other.
Female Players: The number of ways to choose 6 female players out of 8 is calculated using the combination formula which is:
aC(n, k) = n! / (k!(n-k)!)
So, for female players C(8, 6) = 8! / (6! * (8-6)!) = 8! / (6! * 2!) = 28
Male Players: Similarly, for male players: C(7, 5) = 7! / (5! * (7-5)!) = 7! / (5! * 2!) = 21
To find the total number of configurations, we multiply the combinations of females and males together: 28 * 21 = 588.
Therefore, the total number of possible configurations is 588, making Option 1 the correct answer.