Question

Kevin is a party organizer who bought 10 decorations for a marriage party. The prices of the decorations were: $25, $20, $32, $10, $28, $42, $25, $22, $35, and $21. What is the mean absolute deviation of the prices of the decorations?

Answer 1

Explanation:

To find the mean absolute deviation of the prices of the decorations, we need to follow these steps:

1. Calculate the mean of the prices:

Add up all the prices: $25 + $20 + $32 + $10 + $28 + $42 + $25 + $22 + $35 + $21 = $260

Divide the sum by the number of prices (which is 10): $260 / 10 = $26

2. Find the absolute deviation for each price:

Subtract the mean ($26) from each price and take the absolute value of the difference.

Absolute deviation for the first price ($25):

|$25 - $26| = $1

Continue this process for each price to find the absolute deviation.

3. Calculate the mean of the absolute deviations:

Add up all the absolute deviations and divide by the number of prices.

Absolute deviations:

$1, $6, $6, $16, $2, $16, $1, $4, $9, $5

Add them up: $1 + $6 + $6 + $16 + $2 + $16 + $1 + $4 + $9 + $5 = $66

Divide by the number of prices (which is 10):

$66 / 10 = $6.6

So, the mean absolute deviation of the prices of the decorations is $6.6.

Answer 2

25$, 20$, 32$, 10$, 28$, 42$, 25$, 22$, 35$ et 21$. Quel est l'écart moyen absolu des prix des décorations

42-10=32

Explanation: