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A 60% by weight solution of glycerol in water freezes at -28.5oF. Calculate this temperature in degree Celsius.

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Answer:

To convert -28.5°F to degrees Celsius, we can use the formula:

°C = (°F - 32) × 5/9

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Substituting the given value:

°C = (-28.5 - 32) × 5/9

= -60.5 × 5/9

≈ -33.61

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Therefore, a 60% by weight solution of glycerol in water that freezes at -28.5°F is approximately equivalent to -33.61°C

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