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What are the zeros of f(x) = ( x - 1 )(x + 6 ) ?

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put f(x)=0

put f(x)=0 ( x - 1 )(x + 6 )=0

put f(x)=0 ( x - 1 )(x + 6 )=0x= 1, x= -6

User Tamura
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