Final answer:
To minimize the weight of the storage bin, we need to minimize the surface area. By deriving the surface area equation and setting the derivative equal to zero, we find the value of x that minimizes surface area. The surface area that minimizes weight is approximately 3236.37 cm².
Step-by-step explanation:
To minimize the weight of the storage bin, we need to minimize the surface area. Since the base is a square, let's assume the side length of the base is x.
The volume of the storage bin is given as 3500 cm³, which is equal to the product of the base area and height:
V = x² * h = 3500 cm³
To minimize the surface area, we need to find the value of x that minimizes the perimeter of the base and the area of the four side faces.
The surface area, A, of the storage bin is given by:
A = x² + 4xh
Using the volume equation, we can rearrange it to express h in terms of x:
h = 3500 / x²
Substituting this into the surface area equation, we get:
A = x² + 4x(3500 / x²)
Simplifying, we have:
A = x² + 14000 / x
To find the surface area that minimizes weight, we need to find the minimum value of A. We can do this by taking the derivative with respect to x and setting it equal to zero:
dA/dx = 2x - 14000/x² = 0
Multiplying through by x², we have:
2x³ - 14000 = 0
2x³ = 14000
x³ = 7000
x = ∛(7000) ≈ 19.19
Since x represents the side length of the base, we round it to the nearest whole number to get a practical value:
x ≈ 19 cm
The surface area that minimizes weight is then given by substituting this x value into the surface area equation:
A ≈ (19)² + 4(19)(3500/19²) ≈ 289 + 2947.37 ≈ 3236.37 cm²