Final Answer:
The force with which the hammer was swung is 75 Newtons.
Step-by-step explanation:
The force (F) can be calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration
(F = m * a). In this case, the mass (m) of the hammer is 1.5 kg, and the acceleration (a) is the change in velocity over time. Since the hammer is initially at rest, the final velocity (vf) is given as 50 m/s. The initial velocity (vi) is 0 m/s. Therefore, the acceleration (a) is calculated as (vf - vi) / t, where t is the time taken to swing the hammer. Assuming a negligible time for the swing, the acceleration simplifies to 50 m/s. Substituting these values into the formula, we get F = 1.5 kg * 50 m/s = 75 N.
This force of 75 Newtons represents the amount of push or pull applied by the person swinging the hammer. It indicates the impact force with which the hammer hits the wood. Understanding the force involved is crucial for assessing the effectiveness of the swing and ensuring that enough force is applied to drive the nail into the wood securely. In practical terms, the force needed depends on factors like the type of wood, the size of the nail, and the desired outcome of the nailing process.
Question:
The principal begins nailing wood over his office door. The hammer has a mass of 1.5 kg and is swung at 50 m/s. With what force was the hammer swung?