Question

A tennis ball is dropped from 1.54 m above the ground. It rebounds to a heightof 1.03 m. With what velocity does it hit the ground? The acceleration of gravity is 9.8 m/s^2. Let down be negative.

Answer in units of m/s

Answer 1

4.493m/s

Step-by-step explanation:

The first height of 1.54 m is not needed for our final speed

Since the peak of the ball will have a velocity of 0, and our acceleration is 9.8m/s, we can find the final velocity of the ball through algebraic manipulation of the equation the equation

`v_f^2 = v_i^2+2ad\\v_f=√(v_i^2+2ad)\\v_f=√(0^2+2*-9.8*-1.03)\\v_f=4.493m/s`