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How much impulse stops a 52-kg carton sliding at 4.0 m/s when it meets a rough surface?

How much impulse stops a 52-kg carton sliding at 4.0 m/s when it meets a rough surface?
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How much impulse stops a 52-kg carton sliding at 4.0 m/s when it meets a rough surface?

User Svk
by
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1 Answer

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Answer:

208 N * s

Step-by-step explanation:

Δp = m * ΔV

Δp = 52 * (4 - 0)

Δp = 208 N * s

User Narkha
by
8.2k points
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