Final answer:
By using the formulas of geometry and algebra the dimensions of the athletic field are found to be a length of 18 meters and a width of 9 meters.
Step-by-step explanation:
This question is from the field of Mathematics and it deals with the principles of geometry and algebra.
To calculate the dimensions of the athletic field we need to use the given information that the length is twice the width and the perimeter totals 54 meters.
Firstly, let's declare the width as x. It means that the length, being twice the width, would be 2x.
The formula for calculating the perimeter of a rectangle is P = 2L + 2W, in this case we substitute the length and width values so we have 54 = 2(2x) + 2x. This simplifies to 54 = 6x. Solving this equation gives the width x as 9 meters. Since the length is double the width, it is 18 meters.
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