Question

If 5y=-2x+10 was a line what equation would be perpendicular to it
points (-20,4)

Answer 1

y = 5/2x + 54

Explanation:

5y = - 2x + 10

y = -2/5x + 10/5

y = - 2/5x + 2

Slope = -2/5 ( slope of the perpendicular line: negative reciprocal)

Slope of the perpendicular line = 5/2. Point (-20,4)

y-y = m(x-x)

y - 4 = 5/2 (x - - 20

y - 4 = 5/2x + 50

y = 5/2x +54