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To graph the line of the equation y+1=−12(x−4) , first identify the zero of the function. Then use the zero and another point to graph the line. What is the zero of the equation? Type your answer as an ordered pair in the box.

User Willert
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2 Answers

3 votes

Final answer:

To graph the line of the equation y+1=−12(x−4), first identify the zero of the function. Then use the zero and another point to graph the line.

Step-by-step explanation:

To graph the line of the equation y+1=−12(x−4), we need to first identify the zero of the function. The zero of the equation is the value of x for which y = 0. To find it, we set y+1 = 0 and solve for x. Subtracting 1 from both sides, we get y = -1. Therefore, the zero of the equation is (-1, 0).

Next, we can use the zero and another point to graph the line. For example, let's choose x = 0. Substituting this value into the equation, we can solve for y: y + 1 = -12(0 - 4) => y + 1 = 48 => y = 47. So, another point on the line is (0, 47).

Now, we can plot these two points on a graph and draw a line through them to represent the equation. The zero of the equation (-1, 0) and the additional point (0, 47) will help us in graphing the line.

User Killscreen
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1 vote

Answer:

x=4 is the zero of the equation. (3.92,0)

Step-by-step explanation:

y+1 = -12(x-4)

Lets rewrite this in the form of y = mx +b, where m is the slope and b the y-intercept.

y+1 = -12x + 48

y = -12x + 47

The zero of this function is the value of y that causes x to be 0.

0 = -12x + 47

12x = 47

x = 3.92

(3.92,0)

User Dermot
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