Question

A projectile is launched horizontally off a lab table at a speed of 3 m/s. The height of the lab table is 1.5 meters.

How long will the ball be in the air?


use these equations:

ΔX = V0,xt + 1/2axt2
ΔY = V0,yt + 1/2ayt2

Answer 1

0.55 s

Step-by-step explanation:

Take down to be positive. Given in the y direction:

Δy = 1.5 m

v₀ᵧ = 0 m/s

aᵧ = 9.8 m/s²

Find: t

Δy = v₀ᵧ t + ½ aᵧ t²

1.5 = (0) t + ½ (9.8) t²

t = 0.55 s