Question

A random sample of 81 is taken from a population where 70% live in one family homes. What is the probability this sample has p > 0.72?​

Answer 1

To find the probability that a random sample of 81 people from a population, where 70% live in one-family homes, has a sample proportion (p) greater than 0.72:

Calculate the mean (μ) and standard deviation (σ) of the sample proportion p.

μ = 0.70

σ ≈ 0.0509

Find the z-score for 0.72:

z ≈ 0.393

Use a standard normal distribution table or calculator to find P(z > 0.393), which is approximately 0.347 or 34.7%.