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Which of these equations has NO solutions?

A. 3(2x+7)=6(x+4)-3
B. 3(6x-5)=3(6x-5)+x
C. 8(x-3)+14=2(4x+5)
D.13x-7=12(x-1)+x+5

User Mitar
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1 Answer

6 votes

Answer:

C. 8(x-3) + 14 = 2(4x+5).

Explanation:

To determine which equation has no solutions, we need to solve each equation and check if there is a solution. Here's a step-by-step explanation:

A. 3(2x+7) = 6(x+4) - 3

Simplifying both sides:

6x + 21 = 6x + 24 - 3

6x + 21 = 6x + 21

Notice that the variable cancels out on both sides, resulting in a true statement. This equation has infinitely many solutions.

B. 3(6x-5) = 3(6x-5) + x

Simplifying both sides:

18x - 15 = 18x - 15 + x

18x - 15 = 18x - 15 + x

Again, the variable cancels out on both sides, resulting in a true statement. This equation also has infinitely many solutions.

C. 8(x-3) + 14 = 2(4x+5)

Simplifying both sides:

8x - 24 + 14 = 8x + 10

8x - 10 = 8x + 10

The variable cancels out on both sides, resulting in a false statement (-10 ≠ 10). This equation has no solutions.

D. 13x - 7 = 12(x-1) + x + 5

Simplifying both sides:

13x - 7 = 12x - 12 + x + 5

13x - 7 = 13x - 7

The variable cancels out on both sides, resulting in a true statement. This equation has infinitely many solutions.

User Saralynn
by
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