Answer:
Step-by-step explanation:
The lattice energy for francium bromide refers to the energy released when one mole of francium bromide crystals are formed from individual gaseous ions of francium and bromine.
Francium bromide (FrBr) is an ionic compound composed of francium (Fr) cations and bromide (Br) anions. Ionic compounds form strong electrostatic attractions between the positive and negative ions in a crystal lattice structure. The lattice energy quantifies the strength of this attraction.
Calculating the lattice energy involves the use of Coulomb's Law, which states that the force of attraction between two charges is directly proportional to the magnitude of the charges and inversely proportional to the distance between them.
The lattice energy can be determined by considering the charges of the ions and the ionic radii. Since francium is in Group 1 of the periodic table, it has a +1 charge. Bromide, being in Group 17, has a -1 charge.
However, it's important to note that francium is a highly radioactive element with a very short half-life, so it is not readily available for experimental measurements. As a result, the lattice energy for francium bromide is not commonly reported in literature.
In general, the lattice energy of an ionic compound increases with the charges of the ions and decreases with the distance between the ions. Since francium and bromide have opposite charges, the lattice energy for francium bromide would be relatively high. However, without specific experimental data, it is difficult to provide an accurate numerical value for the lattice energy of francium bromide.
It's also worth mentioning that lattice energies are typically negative values because they represent the energy released during the formation of the crystal lattice. However, the precise numerical value for francium bromide would depend on specific experimental measurements and calculations.Ur Beutiful :)