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Consider the system given. If z = 5, find the value of x and y. 2x + 5y + 2 = -7 4x - 5y + 3z = 36 -2x + 4y = -15

User Anjunatl
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1 Answer

5 votes

Answer:

x = 2

y = -13/5

Explanation:

Let's solve this system of equations step by step:

1. We are given that z = 5. We can substitute this value into the second equation:

4x - 5y + 3z = 36

4x - 5y + 3(5) = 36

4x - 5y + 15 = 36

2. Now, let's simplify the second equation:

4x - 5y + 15 = 36

4x - 5y = 36 - 15

4x - 5y = 21

3. We have two equations now:

2x + 5y + 2 = -7

4x - 5y = 21

4. Let's eliminate one variable, either x or y. We'll eliminate y by adding the two equations:

(2x + 5y + 2) + (4x - 5y) = (-7) + 21

2x + 4x + 2 = 14

6x + 2 = 14

5. Now, subtract 2 from both sides to isolate 6x:

6x = 14 - 2

6x = 12

6. Divide both sides by 6 to solve for x:

x = 12 / 6

x = 2

7. Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation:

2x + 5y + 2 = -7

2(2) + 5y + 2 = -7

4 + 5y + 2 = -7

8. Simplify:

5y + 6 = -7

9. Subtract 6 from both sides:

5y = -7 - 6

5y = -13

10. Finally, divide by 5 to solve for y:

y = -13 / 5

So, the solution to the system of equations when z = 5 is:

x = 2

y = -13/5

User Rich Maes
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