Question

A ball is thrown downward from a cliff at 19 m/s. It hits the ground at the base of the cliff 4.1 s later. How high is the cliff?

Answer 1

160 m

Step-by-step explanation:

Given:

u = 19 m/s

a = 9.8 m/s²

t = 4.1 s

Find: s

s = ut + ½ at²

s = (19) (4.1) + ½ (9.8) (4.1)²

s = 160 m