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Find the equation of the line connecting the points (-4,7) and (2,-2)

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To find the equation of the line connecting the points (-4,7) and (2,-2), you can use the point-slope form of a linear equation:

The formula is: y - y1 = m(x - x1)

Where (x1, y1) is one of the points on the line, and m is the slope of the line.

First, calculate the slope (m) using the given points:

m = (y2 - y1) / (x2 - x1)

m = (-2 - 7) / (2 - (-4))

m = (-9) / (2 + 4)

m = -9 / 6

m = -3/2

Now, you can choose either of the two points, let's use (-4, 7):

x1 = -4

y1 = 7

Now, plug these values into the point-slope equation:

y - 7 = (-3/2)(x - (-4))

Simplify further:

y - 7 = (-3/2)(x + 4)

To put it in slope-intercept form (y = mx + b), expand and isolate y:

y - 7 = (-3/2)x - 6

Add 7 to both sides:

y = (-3/2)x + 1

So, the equation of the line connecting the points (-4,7) and (2,-2) is:

y = (-3/2)x + 1

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