Question

Line t has an equation of y+1= 1 8 (x–5). Line u, which is parallel to line t, includes the point (8, – 7). What is the equation of line u?

Answer 1

y=(-18/8)x-(59/9)

Explanation:

make into slope intercept form

y=18x-91

slope of other line = -1/18

plug coords in for b in y=ax+b

y=-(1/18)x+b

-7=-8/18+b

b=-59/9

so line is y=(-18/8)x-(59/9)

Answer 2

y =18x-151

Explanation:

To find the equation of line u, which is parallel to line t, you can use the fact that parallel lines have the same slope. The equation of line t is given as:

y + 1 = 18(x - 5)

We can see that the slope of line t is 18. Now, to find the equation of line u that includes the point (8, -7), you can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where (x1, y1) is the point (8, -7) and m is the slope, which is 18 (the same as line t).

Plugging in the values:

y - (-7) = 18(x - 8)

Now, simplify:

y + 7 = 18(x - 8)

Distribute 18:

y + 7 = 18x - 144

Now, isolate y:

y = 18x - 144 - 7

y = 18x - 151

So, the equation of line u is:

y = 18x - 151