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Find the value of x, de, df, and the measure of DE, EF, and DF.

d, e, and f are collinear

e is between d and f, such that de ≈ fe


de = 5x - 3

df = 8x + 2

1 Answer

2 votes

Answer:

x=4

de=fe=17

df=24

Explanation:

DE = EF

DE + EF = DF

DE + DE = DF

2DE = DF

2(5x-3) = 8x + 2

10x-6 = 8x+2

2x-6 = 2

2x=8

x=4

de=fe=17

df=24

User Karl Jamoralin
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