5 oxygen molecules on the left side and 3 oxygen molecules on the right side in the membrane after equilibrium. Option 2 is the right choice.
Define the initial conditions.
Let's say we start with:
5 oxygen molecules on the left side of the membrane.
3 oxygen molecules on the right side of the membrane.
Assume a constant ratio of oxygen molecules.
At equilibrium, the ratio of oxygen molecules on each side will remain constant. This means the proportion of oxygen molecules on one side compared to the other will stay the same, even though the total number of molecules might change.
Calculate the equilibrium number of molecules.
Let's call this constant ratio r. We can express the number of oxygen molecules on each side at equilibrium as:
Left side: r * (initial left + initial right)
Right side: (initial left + initial right) / r
Plug in the values and solve.
Using the initial values from step 1, we get:
Left side: r * (5 + 3) = 8r
Right side: (5 + 3) / r = 8 / r
Determine the value of r.
We don't actually need to know the exact value of r to find the number of molecules at equilibrium. As long as r is a constant, the following will be true:
The number of molecules on the left side is proportional to 8r.
The number of molecules on the right side is proportional to 8 / r.
Therefore, any of the options that maintain the same ratio between the left and right sides will be the correct answer.
Check the options.
Option 1 (3 on each side) does not maintain the ratio.
Option 2 (5 on the left, 3 on the right) maintains the ratio (5/3 = 8/4).
Option 3 (7 on the left, 4 on the right) does not maintain the ratio.
Option 4 (9 on the left, 6 on the right) does not maintain the ratio.
Therefore, Option 2: 5 oxygen molecules on the left side and 3 oxygen molecules on the right side is the correct answer.
Question:-
How many oxygen molecules are on each side of the membrane after equilibrium?
Option 1: 3
Option 2: 5
Option 3: 7
Option 4: 9