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A ball is thrown horizontally from the top of a tall cliff. Neglecting air drag, what vertical distance has the ball fallen 2.0 seconds later?

User Vcuankit
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Final answer:

Without air resistance, a ball thrown horizontally from a cliff would fall 19.6 meters in 2.0 seconds, calculated using the equation d = ½gt² where g is the acceleration due to gravity.

Step-by-step explanation:

The subject of this question is Physics and it falls within the context of High School grade level. When a ball is thrown horizontally from the top of a cliff and air drag is neglected, the vertical distance the ball would have fallen in 2.0 seconds can be calculated using the equations of motion.

The only force acting on the ball in the vertical direction is gravity. As there is no air resistance, the acceleration due to gravity (g) is approximately 9.8 m/s².

The formula to calculate the distance using the equation of motion is: d = ½gt² Where, d is the distance fallen, g is the acceleration due to gravity and t is the time.

Substitute the given values: d = ½*9.8m/s²*(2.0s)² = 19.6 m.

So, after 2.0 seconds, if air resistance is ignored, the ball would have fallen 19.6 meters vertically from the top of the cliff.

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