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Answer:
If n is a multiple of 3:
Let n = 3a, where a is an integer.
Then n - 1 + n + n + 1 = 3n = 3(3a) = 9a.
If n can be expressed as the sum of 3 consecutive integers:
n = a - 1 + a + a + 1 = 3a, so n is a multiple of 3.
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