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the area of one triangular part of a rhombus abcd formed by two intersecting lines is given as 125cm2. the area of the rhombus abcd is

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Final answer:

The area of a rhombus is twice the area of one of its triangular parts. Therefore, if the area of one triangle is 125 cm², the total area of the rhombus would be 250 cm².

Step-by-step explanation:

The subject of this question is about the area of a rhombus in Mathematics. The area of a rhombus ABCD can be calculated if we know the area of one of its triangular parts. Because a rhombus is bisected into two equal triangular parts by any of its diagonals, the area of the rhombus is effectively twice the area of one of its triangles. So, if the area of a triangle is given as 125 cm², we simply multiply this by two to get the area of the rhombus.

To calculate this:

  1. From the question, the area of one triangular part of the rhombus is 125 cm².
  2. Since a rhombus has two of these equal areas, we multiply the area of one triangle by two.
  3. This gives us 125 cm² x 2 = 250 cm².

Therefore, the area of the rhombus ABCD is 250 cm².

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