Question

a ball rolls across a table at constant velocity. the ball is traveling at speed v. the table is a distance h above the deck below. how far from the edge of the table does the ball travel before it hits the deck?

Answer 1

v √(2h/g)

Step-by-step explanation:

First find the time it takes the ball to fall. Given in the y direction:

s = h

u = 0

a = g

Find: t

s = ut + ½ at²

h = (0) t + ½ (g) t²

t = √(2h/g)

Next, find the distance the ball moves in that time. Given in the x direction:

u = v

a = 0

t = √(2h/g)

Find: s

s = ut + ½ at²

s = (v) √(2h/g) + ½ (0) (2h/g)

s = v √(2h/g)