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A student drops a rock from a bridge to the water 12.0 meters below. How many seconds does it take the rock to hit the water?

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Answer:

Explanation:

To determine the time it takes for the rock to hit the water, we can use the equation of motion for free fall:

[ h = \frac{1}{2}gt^2 ]

Where:

( h ) is the height (12.0 meters in this case)

( g ) is the acceleration due to gravity (approximately 9.8 m/s² on Earth)

( t ) is the time we want to calculate

Rearranging the equation to solve for ( t ), we have:

[ t = \sqrt{\frac{2h}{g}} ]

Substituting the given values, we can calculate the time:

[ t = \sqrt{\frac{2 \times 12.0}{9.8}} \approx 1.22 \text{ seconds} ]

Therefore, it takes approximately 1.22 seconds for the rock to hit the water.

User Sourav Ghosh
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