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If 0.00189 moles of KHP are completely titrated with NaOH, how many moles of NaOH were required?

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Answer:

0.00189 moles of NaOH were required to titrate 0.00189 moles of KHP.

Step-by-step explanation:

To find the number of moles of NaOH required to titrate 0.00189 moles of KHP (potassium hydrogen phthalate), you can use the balanced chemical equation for the reaction between KHP and NaOH:

KHP (C8H5O4K) + NaOH → NaKP (C8H4O4K) + H2O

From the equation, you can see that the molar ratio between KHP and NaOH is 1:1. That means one mole of KHP reacts with one mole of NaOH.

So, if you have 0.00189 moles of KHP, you would need the same number of moles of NaOH for the reaction. Therefore, 0.00189 moles of NaOH were required to titrate 0.00189 moles of KHP.

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