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F(x) = 3x+2, g(x) = (x-3)^2

F(x) = 3x+2, g(x) = (x-3)^2-example-1

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5 votes

Answer:

Explanation:

(a) To find fg(x), we need to substitute g(x) into f(x) and simplify:

f(x) = 3x + 2

g(x) = (x - 3)²

Substituting g(x) into f(x):

fg(x) = f(g(x))

= f((x - 3)²)

Now, let's simplify the expression (x - 3)²:

(x - 3)² = (x - 3)(x - 3)

= x² - 6x + 9

Substituting this back into fg(x):

fg(x) = f((x - 3)²)

= 3(x² - 6x + 9) + 2

= 3x² - 18x + 27 + 2

= 3x² - 18x + 29

Therefore, fg(x) = 3x² - 18x + 29.

(b) To find ¹(-12), we need to substitute x = -12 into the function f(x) and evaluate:

f(x) = 3x + 2

Substituting x = -12:

f(-12) = 3(-12) + 2

= -36 + 2

= -34

Therefore, ¹(-12) = -34.

User Mnesarco
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