Question

In a cross between pea plants that are heterozygous, so they're hybrid for purple flower, what's the probability that the offspring will be homozygous recessive? a. 0% b. 25% c. 50% d. 75% e. 100%

Answer 1

The probability of having an offspring with a homozygous recessive genotype from a cross between two heterozygous pea plants is 25%, according to Mendelian inheritance.

Step-by-step explanation:

The subject of this question is the probability that offspring will be homozygous recessive in a cross between pea plants that are heterozygous for purple flowers. In genetics, when both parents are heterozygous, they possess one dominant and one recessive allele for the given trait. If they are crossed, they create a Punnett square that formulates the probabilities of the offspring's genotype combinations: 25% homozygous dominant, 50% heterozygous, and 25% homozygous recessive.

So, if the heterozygous parents are crossed, the probability that any given offspring will be homozygous recessive is 25%. This pattern of inheritance was first identified by Gregor Mendel in his experiments with pea plants and is known as Mendelian inheritance. Therefore, your answer is: b. 25%.

Learn more about Mendelian inheritance