Question

The capacity of a CD-ROM is 800 MB (800 x 20 raised to 20 bytes). It stores information along a spiral track. If each byte uses a space of 9 microns, what is the length of the complete track in m? (Hint: 1 micron= 10 Raised to-6m)

Answer 1

The length of the complete track=
`7.549* 10^(23) m`

Explanation:

We are given that

Capacity of CD-ROM=800MB=
`800* 20^(20) bytes`

1 byte=9 microns

`1micron=10^(-6)m`

We have to find the length of the complete track in m.

We change MB into micron

`800* 20^(20) bytes=800* 20^(20)* 9microns`

=
`7200* 20^(20) microns`

Now, we change micron into m

`7200* 20^(20) microns=7200* 10^(-6)* 20^(20) m`

=
`7.549* 10^(23) m`

Hence, the length of the complete track=
`7.549* 10^(23) m`