Answer:
Approximately 7.59×10^18 molecules of NH3 are produced from 3.82×10^-4 g of H2.
Step-by-step explanation:
To find the number of molecules of NH3 produced from 3.82×10^-4 g of H2, you need to follow these steps:
Calculate the moles of H2:
Moles = Mass (grams) / Molar Mass (grams/mol)
The molar mass of H2 is approximately 2.02 g/mol.
Moles of H2 = 3.82×10^-4 g / 2.02 g/mol ≈ 1.89×10^-4 moles of H2
Use the balanced chemical equation for the reaction between H2 and NH3:
3H2 + N2 → 2NH3
From the equation, you can see that three moles of H2 produce two moles of NH3.
Calculate the moles of NH3 produced:
Moles of NH3 = (1.89×10^-4 moles of H2) x (2 moles of NH3 / 3 moles of H2) ≈ 1.26×10^-4 moles of NH3
Calculate the number of molecules of NH3 using Avogadro's number (6.022×10^23 molecules/mol):
Number of molecules = Moles x Avogadro's number
Number of molecules = (1.26×10^-4 moles) x (6.022×10^23 molecules/mol) ≈ 7.59×10^18 molecules of NH3
So, approximately 7.59×10^18 molecules of NH3 are produced from 3.82×10^-4 g of H2.