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How many molecules (not moles) of NH3 are produced from 3.82×10−4 g of H2?

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Answer:

Approximately 7.59×10^18 molecules of NH3 are produced from 3.82×10^-4 g of H2.

Step-by-step explanation:

To find the number of molecules of NH3 produced from 3.82×10^-4 g of H2, you need to follow these steps:

Calculate the moles of H2:

Moles = Mass (grams) / Molar Mass (grams/mol)

The molar mass of H2 is approximately 2.02 g/mol.

Moles of H2 = 3.82×10^-4 g / 2.02 g/mol ≈ 1.89×10^-4 moles of H2

Use the balanced chemical equation for the reaction between H2 and NH3:

3H2 + N2 → 2NH3

From the equation, you can see that three moles of H2 produce two moles of NH3.

Calculate the moles of NH3 produced:

Moles of NH3 = (1.89×10^-4 moles of H2) x (2 moles of NH3 / 3 moles of H2) ≈ 1.26×10^-4 moles of NH3

Calculate the number of molecules of NH3 using Avogadro's number (6.022×10^23 molecules/mol):

Number of molecules = Moles x Avogadro's number

Number of molecules = (1.26×10^-4 moles) x (6.022×10^23 molecules/mol) ≈ 7.59×10^18 molecules of NH3

So, approximately 7.59×10^18 molecules of NH3 are produced from 3.82×10^-4 g of H2.

User Gleb Bahmutov
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