Question

In a calorimetry experiment, an unknown mass of glass (c = 0.8372 J/g oC) at 90.0 oC is dropped into a calorimeter (c = 1.23 J/g oC, m = 7.0 g) that contains 75.0 g of water. If the temperature increases from 24.3 oC at the beginning of the experiment to 26.6 C by the end, what was the mass of the glass?

Answer 1

To solve this problem, we can use the calorimetry formula that relates the heat transfer between the system and the surroundings:

Q = mc∆T

where Q is the heat transfer, m is the mass, c is the specific heat capacity, and ∆T is the temperature change.

We can assume that the heat lost by the glass and the calorimeter is equal to the heat gained by the water. Therefore, we can write:

Qglass + Qcalorimeter = Qwater

Substituting the values given in the problem, we get:

mglass x 0.8372 x (26.6 - 90) + 7 x 1.23 x (26.6 - 24.3) = 75 x 4.184 x (26.6 - 24.3)

Solving for mglass, we get:

mglass = 10.8 g

Therefore, the mass of the glass was 10.8 g.

I hope this answer helps you understand how to use the calorimetry formula to find the mass of an object. Thank you for chatting with me.