Question

£

A sample that was believed to be a
mixture of I and Te was run through
a mass spectrometer, resulting in the
data opposite.
All of the following statements are true.
Which one would be the best basis for
concluding that the sample was pure Te?
A
B
The elements I and Te have similar
average atomic masses.
C
D
Relative Abundance (%)
25
15
V
0
122 123 124 125 126 127 128 129 130
Mass Number (uma)
Te forms lons with a -2 charge, whereas I forms ions with a -1 charge.
Te is more abundant than I in the universe.
I consists of only one naturally occurring isotope with 74 neutrons,
whereas Te has more than one isotope.
I has a higher first ionization energy than Te does

Answer 1

The best basis for concluding that the sample was pure Te is option C:

C. I consists of only one naturally occurring isotope with 74 neutrons, whereas Te has more than one isotope.

This statement suggests that I (iodine) has only one naturally occurring isotope with a mass number of 127 (which is close to the average atomic mass of iodine), while Te (tellurium) has multiple isotopes with different mass numbers. The mass spectrometer data shows a dominant peak at mass number 127, which aligns with the natural abundance of Te isotopes. This indicates that the sample likely consists mainly of tellurium (Te), making option C the most suitable basis for concluding that the sample was pure Te.

Step-by-step explanation:

if you need a personal homework helper.