Question

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A ball is initially at rest and travels 9.9 m.
The ball travels at an acceleration of 6.1
m/s².
What is the final velocity of the ball?
Give your answer to 1 decimal place.
Final velocity=
0/1

Answer 1

To find the final velocity of the ball, you can use the following equation of motion:

\[v^2 = u^2 + 2as\]

Where:

- \(v\) is the final velocity.

- \(u\) is the initial velocity (which is 0 m/s because the ball is initially at rest).

- \(a\) is the acceleration (6.1 m/s²).

- \(s\) is the distance traveled (9.9 m).

Plugging in these values:

\[v^2 = (0)^2 + 2(6.1 m/s²)(9.9 m)\]

Now, calculate:

\[v^2 = 2(6.1 m/s²)(9.9 m) = 119.58 m^2/s^2\]

Take the square root to find \(v\):

\[v = \sqrt{119.58} \approx 10.95 \, \text{m/s}\]

So, the final velocity of the ball is approximately 10.95 m/s (rounded to one decimal place).