88.7k views
0 votes
Calculator

A ball is initially at rest and travels 9.9 m.
The ball travels at an acceleration of 6.1
m/s².
What is the final velocity of the ball?
Give your answer to 1 decimal place.
Final velocity=
0/1

User BrianC
by
8.5k points

1 Answer

4 votes

Answer:

To find the final velocity of the ball, you can use the following equation of motion:

\[v^2 = u^2 + 2as\]

Where:

- \(v\) is the final velocity.

- \(u\) is the initial velocity (which is 0 m/s because the ball is initially at rest).

- \(a\) is the acceleration (6.1 m/s²).

- \(s\) is the distance traveled (9.9 m).

Plugging in these values:

\[v^2 = (0)^2 + 2(6.1 m/s²)(9.9 m)\]

Now, calculate:

\[v^2 = 2(6.1 m/s²)(9.9 m) = 119.58 m^2/s^2\]

Take the square root to find \(v\):

\[v = \sqrt{119.58} \approx 10.95 \, \text{m/s}\]

So, the final velocity of the ball is approximately 10.95 m/s (rounded to one decimal place).

User Rahulmohan
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.