Answer:
To find the final velocity of the ball, you can use the following equation of motion:
\[v^2 = u^2 + 2as\]
Where:
- \(v\) is the final velocity.
- \(u\) is the initial velocity (which is 0 m/s because the ball is initially at rest).
- \(a\) is the acceleration (6.1 m/s²).
- \(s\) is the distance traveled (9.9 m).
Plugging in these values:
\[v^2 = (0)^2 + 2(6.1 m/s²)(9.9 m)\]
Now, calculate:
\[v^2 = 2(6.1 m/s²)(9.9 m) = 119.58 m^2/s^2\]
Take the square root to find \(v\):
\[v = \sqrt{119.58} \approx 10.95 \, \text{m/s}\]
So, the final velocity of the ball is approximately 10.95 m/s (rounded to one decimal place).