Find the perimeter of a rectangle with a width of 2x^2+4x-8 and a length of 3x+8. A.2x^2+7x B.4x^2+14x C.4x^2+14x+32 C.18x^2

asked Jul 14, 2022 195k views

15 votes

Find the perimeter of a rectangle with a width of 2x^2+4x-8 and a length of 3x+8.

A.2x^2+7x

B.4x^2+14x

C.4x^2+14x+32

C.18x^2

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11 votes

Answer:

B . 4x^2 + 14x

Explanation:

2(2x^2+4x-8) + 2(3x+8)

=4x^2 +8x-16+6x+16

=4x^2+14 (ans)

Dest answered Jul 19, 2022

by Dest

6.1k points

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