Answer:
you need tomix 80 mL of the 80% acid solution with 120 mL of the 30% solution to produce 200 mL of a 50% solution.
Explanation:
Let x be the amount (in mL) of the 80% solution to be mixed with the 30% solution.
Here's the equation based on the amount of acid in each solution:
0.80x (acid from the 80% solution) + 0.30(200 - x) (acid from the 30% solution) = 0.50(200) (acid in the final 50% solution)
Now, let's solve for x:
0.80x + 60 - 0.30x = 100
Combine like terms:
0.50x + 60 = 100
Subtract 60 from both sides:
0.50x = 100 - 60
0.50x = 40
Now, divide by 0.50 to isolate x:
x = 40 / 0.50
x = 80